Trisectrix of Maclaurin
TRISECTRIX OF MACLAURIN

Balmoral Software

The lobe of the Trisectrix of Maclaurin is a convex x-symmetric droplet-shaped closed curve S with polar equation
r(t) = 4 cos(t) - sec(t), -π/3 ≤ t < π/3
The curve follows a counterclockwise path as t increases, starting from the cusp at the origin when t = -π/3, proceeding through Quadrant IV to the right edge (3,0) at t = 0, then following a symmetric path through Quadrant I back to the cusp at t = π/3. The maximum ordinate point of S is
so the width x height of its bounding rectangle is

### Metrics

The area of S is
and its perimeter is 8.244653. By (C2), its centroid abscissa is

### Incircle

The maximum radius of a circle centered on the x-axis and inscribed in S is its maximum ordinate, so a candidate for the incircle has radius
and center abscissa The candidate circle must be contained within S, so we require that c - R and c + R both be within the abscissa range [0,3] of S, which is true. For verification, we have

### Inellipse

Using z = 3 in Lemma E,
d/dt [x(t) - z]y(t) = d/dt -4sin2(t)tan(t)[2cos(2t) + 1]
has a zero at t* = π/4. The corresponding coordinates are (x*,y*) = (1,1). We then have
For verification,

### Circumellipse

Using z = 0 in Lemma E,
d/dt [x(t) - z]y(t) = d/dt [4cos(t) - sec(t)]2cos(t)sin(t)
has a zero at
The corresponding coordinates are
We then have
For verification,

### Circumcircle

Since the abscissa extrema are on the x-axis and the bounding rectangle is wider than it is tall, a candidate for the circumcircle has its radius and center abscissa both equal to 3/2. For verification, we have

### Summary Table

 Perimeter Area Centroid Figure Parameters Incircle R = 7.413905 4.374055 (1.732051,0) Inellipse 7.826465 4.836799 (1.666667,0) Trisectrix 8.244653 5.196152 (1.612266,0) Circumellipse 8.689052 5.892208 (1.535184,0) Circumcircle R = 3/2 9.424778 7.068584 (1.5,0)

The Trisectrix of Maclaurin (red) is a member of a group of similarly-shaped figures described on these pages, including (inside to outside) the teardrop curve, the Tschirnhausen cubic, the right strophoid and the piriform curve:

### Relationship with the Folium of Descartes

The Folium of Descartes coincides with the Trisectrix of Maclaurin after a rotation and non-uniform scaling of the coordinates. The polar equation of the Folium
is rotated clockwise by π/4, producing the new x-symmetric polar function
Over the lobe domain -π/4 ≤ t < π/4, the maximum abscissa and ordinate of the rotated Folium are
so to scale the Folium to the comparable coordinate extrema of the trisectrix, we multiply its abscissas by 3/xmax and its ordinates by producing the coordinate functions
These coordinate functions cannot be directly compared with the corresponding ones for the trisectrix since the rates of travel along the path (if t is considered a time variable) vary between the two curves, and the domains for t are different. However, the path itself is the same for both curves since the preceding x(t), y(t) satisfy the cartesian form of the trisectrix:
2x(x2 + y2) = 2(3x2 - y2)