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r(t) = 4 cos(t) - sec(t), -π/3 ≤ t < π/3The curve follows a counterclockwise path as t increases, starting from the cusp at the origin when
so the width x height of its bounding rectangle is![]()
and its perimeter is 8.244653. By (C2), its centroid abscissa is![]()
and center abscissa![]()
d/dt [x(t) - z]y(t) = d/dt -4sin2(t)tan(t)[2cos(2t) + 1]has a zero at t* = π/4. The corresponding coordinates are (x*,y*) = (1,1). We then have
For verification,![]()
d/dt [x(t) - z]y(t) = d/dt [4cos(t) - sec(t)]2cos(t)sin(t)has a zero at
The corresponding coordinates are![]()
We then have![]()
For verification,![]()
Figure Parameters Perimeter Area Centroid Incircle R = 7.413905 4.374055 (1.732051,0) Inellipse 7.826465 4.836799 (1.666667,0) Trisectrix 8.244653 5.196152 (1.612266,0) Circumellipse 8.689052 5.892208 (1.535184,0) Circumcircle R = 3/2 9.424778 7.068584 (1.5,0)
The Trisectrix of Maclaurin (red) is a member of a group of similarly-shaped figures described on these pages, including (inside to outside) the teardrop curve, the Tschirnhausen cubic, the right strophoid and the piriform curve:
is rotated clockwise by π/4, producing the new x-symmetric polar function![]()
Over the lobe domain -π/4 ≤ t < π/4, the maximum abscissa and ordinate of the rotated Folium are![]()
so to scale the Folium to the comparable coordinate extrema of the trisectrix, we multiply its abscissas by 3/xmax and its ordinates by![]()
These coordinate functions cannot be directly compared with the corresponding ones for the trisectrix since the rates of travel along the path (if t is considered a time variable) vary between the two curves, and the domains for t are different. However, the path itself is the same for both curves since the preceding x(t), y(t) satisfy the cartesian form of the trisectrix:![]()
2x(x2 + y2) = 2(3x2 - y2)
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