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r(t) = 2cos(t) - sec(t), -π/4 ≤ t < π/4The curve follows a counterclockwise path as t increases, starting from the cusp at the origin when
so the width x height of its bounding rectangle is
A = (4 - π)/2We have
r'(t) = -2sin(t) - tan(t)sec(t),so by (L2), the perimeter of S is
By (C2), its centroid abscissa is
and center abscissa The candidate circle must be contained within S, so we require that
d/dt [x(t) - z]y(t) = d/dt -2sin2(t)cos(2t)tan(t)has a zero at
The corresponding coordinates are
We then have
For verification,
d/dt [x(t) - z]y(t) = d/dt cos2(2t)tan(t)has a zero at
The corresponding coordinates are
We then have
For verification,
Figure Parameters Perimeter Area Centroid Incircle R = 1.886734 0.283277 (0.618034,0) Inellipse 2.252459 0.382312 (0.577350,0) Right strophoid 2.4896 0.429204 (0.553264,0) Circumellipse 2.668302 0.517274 (0.520518,0) Circumcircle R = 1/2 3.141593 0.785398 (0.5,0)
The right strophoid (red) is a member of a group of similarly-shaped figures described on these pages, including (inside to outside) the teardrop curve, the Tschirnhausen cubic, the Trisectrix of Maclaurin and the piriform curve:
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