For a circle of radius r, we have
A = π r2 = 2π r = Por
r = 2The associated area and perimeter are 4π.
A bicylinder is the orthogonal intersection of two cylinders having the same radius. If r is the radius, then
V = (16/3)r3 = 16r2 = S,or
r = 3The associated volume and surface area are 144.
For a sphere of radius r, we have
V = (4/3)π r3 = 4π r2 = SThe associated volume and surface area are 36π. This sphere is a solid of revolution of a non-equable closed semicircle with perimeter
r = 3
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