*Balmoral Software*

For a circle of radius r, we have

A = π ror^{2}= 2π r = P

r = 2The associated area and perimeter are 4π.

A bicylinder is the orthogonal intersection of two cylinders having the same radius. If r is the radius, then

V = (16/3)ror^{3}= 16r^{2}= S,

r = 3The associated volume and surface area are 144.

For a sphere of radius r, we have

V = (4/3)π rThe associated volume and surface area are 36π. This sphere is a solid of revolution of a non-equable closed semicircle with perimeter^{3}= 4π r^{2}= Sr = 3

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